# What is the force, in terms of Coulomb's constant, between two electrical charges of 8 C and -15 C that are 9 m  apart?

##### 1 Answer
Jun 19, 2018

$- 1.48 \setminus {\text{C"^2"/m}}^{2} \cdot k$

#### Explanation:

Coulomb's law states that:

$F = k \frac{{q}_{1} {q}_{2}}{r} ^ 2$

where:

• $k$ is Coulomb's constant

• ${q}_{1} , {q}_{2}$ are the charges of the two charges

• $r$ is the distance between the two charges

So, we get:

F=k(8 \ "C"*-15 \ "C")/((9 \ "m")^2)

$= \left(- 120 \setminus {\text{C"^2*k)/(81 \ "m}}^{2}\right)$

$= - 1.48 \setminus {\text{C"^2"/m}}^{2} \setminus k$