# What is the force, in terms of Coulomb's constant, between two electrical charges of -6 C and -9 C that are 9 m  apart?

The force $F = \frac{2}{3} {k}_{e}$
where ${k}_{e} = 8.99 {\text{ x "10^9" " "Newton" * "meter"^2*"Coulomb}}^{- 2}$

#### Explanation:

The formula for the force

$F = {k}_{e} \frac{\left\mid {q}_{1} {q}_{2} \right\mid}{r} ^ 2$

where ${k}_{e} = 8.99 {\text{ x "10^9" " "Newton" * "meter"^2*"Coulomb}}^{- 2}$

$F = {k}_{e} \frac{\left\mid {q}_{1} {q}_{2} \right\mid}{r} ^ 2$

$F = {k}_{e} \frac{\left\mid \left(- 6\right) \left(- 9\right) \right\mid}{{9}^{2}}$

$F = \frac{2}{3} {k}_{e}$

The actual numerical value $F = 5.99333$ x ${10}^{9}$ Newtons

God bless....I hope the explanation is useful.