# What is the force, in terms of Coulomb's constant, between two electrical charges of 16 C and -6 C that are 12 m  apart?

May 7, 2016

$F = - {6.10}^{9} N$

#### Explanation:

$\text{force between two charges is given as:}$

$F = k \cdot \frac{{q}_{1} \cdot {q}_{2}}{r} ^ 2$

$F = {9.10}^{9} \frac{16 \cdot \left(- 6\right)}{12} ^ 2$

$F = - \frac{9 \cdot {96.10}^{9}}{144}$

$F = - {6.10}^{9} N$