# What is the force, in terms of Coulomb's constant, between two electrical charges of -4 C and 32 C that are 12 m  apart?

Mar 8, 2017

$| F | \approx 2.5 \cdot {10}^{7} N$

#### Explanation:

The force between two charges is given by Coulomb's Law:

$| F | = k \frac{| {q}_{1} | | {q}_{2} |}{r} ^ 2$

Where $k$ is a constant equal to $8.99 \cdot {10}^{9} \frac{N \cdot {m}^{2}}{C} ^ 2$

We are given that $r = 12.0 m , {q}_{1} = - 4 C ,$ and ${q}_{2} = 32 C$.

$\implies | F | = \left(8.99 \cdot {10}^{9} \frac{N \cdot {m}^{2}}{C} ^ 2\right) \frac{\left(4 C\right) \left(32 C\right)}{12.0 m} ^ 2$

$\approx 2.5 \cdot {10}^{7} N$