# What is the force, in terms of Coulomb's constant, between two electrical charges of 44 C and 19 C that are 12 m  apart?

May 3, 2017

The force is $= \left(5.81 k\right) N$

#### Explanation:

Here,

The first charge is ${q}_{1} = 44 C$

The second charge is ${q}_{2} = 19 C$

The distance is $r = 12 m$

The force is

$F = k \cdot \frac{44 \cdot 19}{12} ^ 2$

$= 5.81 k N$