What is the force, in terms of Coulomb's constant, between two electrical charges of #2# #C# and #-14# #C# that are #15# #m # apart?

1 Answer
Jan 25, 2016

Answer:

The force between two charged particles a distance #r# #m# apart is given by #F=(kq_1q_2)/r^2# where #k# is Coulomb's constant. The answer is #F=(k*2*(-14))/15^2 = (-28k)/15^2 =(-28k)/225#

Explanation:

I'm not sure I can add much more explanation on this one. We were asked for an answer 'in terms of Coulomb's constant', so we've left #k# as #k# rather than substitute in its value of #9.0xx10^9 Nm^2C^-2#.

The negative sign of the answer just means the two objects experience a force attracting them to each other, because they have opposite charges, rather than a force repelling them, as they would if their charges were the same.