Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `18 C` and `-14 C` that are `15 m` apart?

Answer 1

This is solved using Coulomb's Law, `F_e=(kq_1q_2)/r^2`

Explanation:

The force, in this case attraction (since the charges are opposite), is given by

`F_e=(kq_1q_2)/r^2`

where `k` is the constant `8.99*10^9 (Nm^2)/C^2`
`q_1` and `q_2` are the charges (18C and -14C)
and r is the distance between them, in this case 15 m.

I think you will find it to be an absurdly large number.