# What is the force, in terms of Coulomb's constant, between two electrical charges of 18 C and 35 C that are 15 m  apart?

Apr 24, 2016

$2.8 K$

#### Explanation:

Electromagnetic force is given by

$F = K \frac{{q}_{a} \cdot {q}_{b}}{r} ^ 2$,

where $F$ is force, $q$ is the magnitude of either charge, $K$ is Coulomb's constant, and $r$ is the distance between them.

Using values from the question,

$F = K \frac{18 \cdot 35}{15} ^ 2 = \frac{630}{225} K = 2.8 K$