Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `-225 C` and `-75 C` that are `15 m` apart?

Answer 1

`6.75xx10^11` Newtons repulsive force

Explanation:

Coulombs force `F=1/(4πε_0) (q_1 q_2)/r^2`
Here `1/(4πε_0)` is a constant with the value of `9xx10^9` `Nm^2C^-2`

Substituting the values `F=9xx10^9 (-225xx-75)/15^2`
=`6.76xx10^11` `N`

As the result is positive the force between the charges would be repulsive.