# What is the force, in terms of Coulomb's constant, between two electrical charges of -225 C and -75 C that are 15 m  apart?

Jan 17, 2016

$6.75 \times {10}^{11}$ Newtons repulsive force

#### Explanation:

Coulombs force F=1/(4πε_0) (q_1 q_2)/r^2
Here 1/(4πε_0) is a constant with the value of $9 \times {10}^{9}$ $N {m}^{2} {C}^{-} 2$

Substituting the values $F = 9 \times {10}^{9} \frac{- 225 \times - 75}{15} ^ 2$
=$6.76 \times {10}^{11}$ $N$

As the result is positive the force between the charges would be repulsive.