Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `-225 C` and `-15 C` that are `15 m` apart?

Answer 1

`15k` `N`

Explanation:

Electrostatic force is given by `F=(kQ_1Q_2)/r^2`, where:

• `k` = coulomb's constant (`8.99*10^9Nm^2C^-2`)
• `Q` = charge (`C`)
• `r` = distance between the point charges (`m`)

`F=(k(-225)(-15))/15^2=(k225)/15=15k` `N`