# What is the formula for manganese(IV) oxide?

Apr 19, 2016

$M n {O}_{2}$
The roman numeral IV in front of manganese tells us that it is oxidizing at ${4}^{+}$. Looking at the table, oxygen is a group 16 element which means it oxidizes at a ${2}^{-}$ state, To neutralize the oxidation number of manganese, two atoms of oxygen should be added to achieve the final compound $M n {O}_{2}$.