What is the fourth term in the expansion of the binomial #(2x+y^2)^5#?

1 Answer
Jun 27, 2017

#40x^2y^6#

Explanation:

#"using the "color(blue)"binomial theorem"#

#• (x+y)^n=sum_(r=0)^n((n),(r))x^(n-r)y^r#

#"where " ((n),(r))=(n!)/(r!(n-r)!)#

#"the general term is " ((n),(r))x^(n-r)y^r#

#"and " T_(r+1)=((n),(r))x^(n-r)y^r#

#"here " x=2x" and " y=y^2#

#• color(blue)" for fourth term use r=3"#

#rArrT_4=((5),(3))(2x)^2(y^2)^3#

#color(white)(rArrT_4)=10xx4x^2xxy^6#

#color(white)(rArrT_4)=40x^2y^6#