# What is the grams of sodium in NaCrO_4?

In one mole of bright yellow sodium chromate, $N {a}_{2} C r {O}_{4}$, there are approx. 46 g sodium
The chromate ion, $C r {O}_{4}^{2 -}$, forms a disodium salt, $N {a}_{2} C r {O}_{4}$.
The equivalent weight of this substance is $161.97$ $g \cdot m o {l}^{-} 1$, of which $46$ $g$ are sodium ions. What is the percentage by mass of sodium in this substance?