# What is the heat capacity of a piece of wood if 1500 g of the wood absorbs 67,500 joules of heat, and its temperature changes from 32°C to 57°C?

May 13, 2016

$Q = m \cdot c \cdot \Delta t$

#### Explanation:

The amount of heat absorbed is given by:

$Q = m \cdot c \cdot \Delta t$

Where:

$m \text{ is the mass of the wood}$
$c \text{ is the specific heat capacity}$
$\Delta t \text{ is the change in temperature}$

Solve for c;

c=Q/(m*Deltat"

$c = \frac{67500 J}{1500 g \cdot {25}^{o} C}$

$c = 1.8 \frac{J}{g} ^ o C$