What is the heat capacity of a piece of wood if 1500 g of the wood absorbs 67,500 joules of heat, and its temperature changes from 32°C to 57°C?

1 Answer
May 13, 2016

Q=m*c*Delta t

Explanation:

The amount of heat absorbed is given by:

Q=m*c*Delta t

Where:

m " is the mass of the wood"
c " is the specific heat capacity"
Deltat " is the change in temperature"

Solve for c;

c=Q/(m*Deltat"

c=(67500J)/(1500g*25^oC)

c= 1.8 J/g^oC