What is the Iinear speed of a point on Earth's equator? What if the point was at latitude -15.0° ?
At the equator, linear speed with respect to the polar (day/night spin ) axis is 463.82 meter/s = 1521.8 feet/s, At latitude
In the day-night spin, any point on the Earth moves around Earth's
axis in its latitude circle.
Speed = (distance traveled in a second)/second..
The circumference of the equator =
The number of seconds in a day = 24 X 3600
So, at the equator, speed =
0.46382 km/s = 463.82 meter/s = 1521.8 feet/s.
6374.5 km, nearly.
The latitude-circle circumference
So, the speed is (
0.44777 km/s = 447.77 meter/s = 1469.1 feet/s
Thanks to Johannes C for pointing to the error in the unit km,
used for meter, in my earlier edition...