Question

What is the instantaneous velocity of an object moving in accordance to `f(t)= (e^(t^2),2t-te^t)` at `t=-1`?

Answer 1

`f'(-1)=(-2e,2)`.

Explanation:

The law `f(t)` is the position of the object at the time `t`.

To find the instantaleous velocity we have to find the derivative of the previous law.

`f'(t)=(2te^(t^2),2-e^t-te^t)`

and so:

`f'(-1)=(-2e,2-1/e+1/e)=(-2e,2)`.