What is the integral from 0 to 16 of #1/(16-x) dx#?
The improper integral
Or, if you have extended the definition of integral to include improper integral, then the textbook should say that the integral diverges.
If your course has covered logarithms and improper integrals, then here is the work:
#= lim_(brarr16^-) -ln(16-x) ]_0^b#
#= lim_(brarr16^-) (-ln(16-b) + ln (16))#
so we have
the integral diverges.