What is the integral of #e^(0.5x)#?

2 Answers

Answer:

#2e^{0.5x}+C#

Explanation:

#\int e^{0.5x}\ dx#

#=\int e^{0.5x}1/0.5d(0.5x)#

#=1/0.5\int e^{0.5 x}\ d(0.5x)#

#=2e^{0.5x}+C#

Jul 18, 2018

Answer:

#2e^(1/2x)+C#

Explanation:

Substiting #t=1/2x# we get

#x=2t# so #dx=2dt# and our integral is given by #2int e^tdt=2e^t+C=2e^(1/2x)+C#