What is the integration of 1/x3?

1 Answer
Feb 25, 2018

-1/(2x^2)+c12x2+c

Explanation:

to find the integral of given function we have to use the formula
int x^n= x^(n+1)/(n+1)+cxn=xn+1n+1+c

Here we have n=-3, so
int1/x^3=intx^-3=x^(-3+1)/(-3+1)=x^-2/-2=-1/(2x^2) +c.1x3=x3=x3+13+1=x22=12x2+c.