Question

What is the integration of 1/x3?

Answer 1

`-1/(2x^2)+c`

Explanation:

to find the integral of given function we have to use the formula
`int x^n= x^(n+1)/(n+1)+c`

Here we have n=-3, so
`int1/x^3=intx^-3=x^(-3+1)/(-3+1)=x^-2/-2=-1/(2x^2) +c.`