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What is the interior angle of a regular 21-gon? (Round to 2 decimal places.)

1 Answer

Apr 2, 2018

The interior angle of a regular 21-gon is around ${162.86}^{\circ}$ $162.86^@$ .

Explanation:

The sum of interior angles in a polygon with n corners is

$180 (n - 2)$ $180(n-2)$

A 21-gon therefore has an interior angle sum of:

$180 (21 - 2) = 180 \cdot 19 = 3420^{\circ}$ $180(21-2)=180*19=3420^@$

In a regular 21-gon, all interior angles are equal, so we can find out the measure of one of these angles by dividing $3420$ $3420$ by $21$ $21$ :

$\frac{3420}{21} \approx 162.86$ $3420/21~~162.86$

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