#"first find the median and the lower/upper quartiles"#
#"the median is the middle value of the data set "#
#"arrange the data set in ascending order"#
#8color(white)(x)9color(white)(x)color(red)(10)color(white)(x)11color(white)(x)12#
#rArr"the median "=10#
#"the lower quartile is the middle value of the data to the"#
#"left of the median. If there is no exact value then it is the"#
#"average of the values on either side of the middle"#
#"the upper quartile is the middle value of the data to the"#
#"right of the median. If there is no exact value then it is the"#
#"average of the values on either side of the middle"#
#8color(white)(x)color(purple)(uarr)color(white)(x)9color(white)(x)color(red)(10)color(white)(x)11color(white)(x)color(purple)(uarr)color(white)(x)12#
#"lower quartile "(Q_1)=(8+9)/2=8.5#
#"upper quartile "(Q_3)=(11+12)/2=11.5#
#"interquartile range "=Q_3-Q_1=11.5-8.5=3#