What is the inverse function of #f(x) =5x^3 + 4x^2 + 3x + 4#?

1 Answer
Jan 2, 2016

#x=5y^3+4y^2+3y+4#

Explanation:

The simplest way to write the inverse function is to write #y# in place of #f(x)# and switch all the #x#s with #y#s and the #y# with #x#, giving:

#x=5y^3+4y^2+3y+4#

This can be written explicitly (in terms of #y#), but it uses the incredibly cumbersome cubic formula and is overall unhelpful. But, for the sake of interest, it's as follows:

#x=-(15 sqrt(3) sqrt(675 y^2-4576 y+7900)-675 y+2288)^(1/3)/(15 (2^(1/3)))+(29 (2^(1/3)))/(15 (15 sqrt(3) sqrt(675 y^2-4576 y+7900)-675 y+2288)^(1/3))-4/15#

Graph:
http://www.wolframalpha.com/input/?i=y%3D5x^3%2B4x^2%2B3x%2B4+inverse