What is the inverse function of #y = (x+1) / x#?
1 Answer
Jul 12, 2018
Explanation:
#"rearrange making x the subject"#
#xy=x+1#
#xy-x=1#
#x(y-1)=1#
#x=1/(y-1)rArrf^-1(x)=1/(x-1)#
#"rearrange making x the subject"#
#xy=x+1#
#xy-x=1#
#x(y-1)=1#
#x=1/(y-1)rArrf^-1(x)=1/(x-1)#