What is the inverse of #(4x-1)/x#?

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Answer 1 · 2016-09-13T19:42:29

#x/(4x-1)#

However, if you meant invers function that is a very different game.

Answer 2 · 2016-09-13T20:58:33

You need to specify which inverse is required.

More detail is required before there can be one answer to this question. There are different types of inverses:

ADDITIVE INVERSES add to make 0.

The additive inverse of #(4x-1)/x " is " -(4x-1)/x#

MULTIPLICATIVE INVERSES multiply to give 1.
They are also known as Reciprocals.

The multiplicative inverse of #(4x-1)/x " is " x/(4x-1)#

The inverse of a function can only be found if it is known that

#f(x) = (4x-1)/x#