What is the Ksp and Kf of #Zn(H_2O)_6# ?

1 Answer
Mar 26, 2017

Answer:

Well #K_"sp"# is unknown..........

Explanation:

I think you refer to the zinc ion in water, which we should represent as #[Zn(OH_2)_6]^(2+)#. Salts such as #ZnCl_2# are mighty soluble in water (you'll have to dig for the details), but if we represent its solubility as #S#,

then according to the solubility equation:

#ZnCl_2(s) + "excess"H_2OrightleftharpoonsZn^(2+)+2Cl^(-)#

And so #K_"sp"=[Zn^(2+)][Cl^-]^2#

And reasonably, we can equate the solubility of the salt, #S#, with #[Zn^(2+)]#. Do you agree?

And so, finally, we write, #K_"sp"=Sxx(2S)^2=4S^3#.

#K_"f"(Zn^(2+)(aq))# is a trickier proposition.