#color(blue)("Dealing with just the variables part")#
#color(green)(10w^2u^3)# and #color(maroon)(25w^6u^4y^7)#
Consider the #color(green)(u^3) and color(maroon)(u^4)#
#3xx4=12# so a possible target is #u^12#
Consider the #color(green)(w^2) and color(darkgoldenrod)(w^6)#
#2xx6=12# so a possible target is #w^12#
set the target as #w^12u^12y^7#
#color(magenta)(w^6u^4y^yxx)color(green)(w^2u^3) =w^12u^12y^7#
#color(magenta)(w^2u^3xx)color(maroon)(w^6u^4y^7) = w^12u^12y^7 #
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#color(blue)("Dealing with just the number part")#
We have 10 and 25. As one of these values than the last digit of the LCM has to be 0
The first multiple of 25 that gives a last digit of 0 is: #2xx25=50#
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#color(blue)("Putting it all together")#
LCM #= 50w^12u^12y^7#
