# What is the leading term, leading coefficient, and degree of this polynomial f(x)= x^2(sqrt2) + x - 5?

Apr 11, 2018

Leading term $\sqrt{2} {x}^{2}$, Leading coefficient: $\sqrt{2}$, Degree $2$.

#### Explanation:

$f \left(x\right) = {x}^{2} \left(\sqrt{2}\right) + x + 5$

We can write this as:

$f \left(x\right) = \sqrt{2} {x}^{2} + x + 5$

This is a quadratic in standard form: $a {x}^{2} + b x + c$
Where: $a = \sqrt{2} , b = 1 \mathmr{and} c = 5$

Hence, Leading term: $\sqrt{2} {x}^{2}$ and leading coefficient: $\sqrt{2}$.

Also, a quadratic function is of degree 2, since the leading term is of $x$ to the power $2$