What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?

Jul 20, 2017

The length is $= 1.20144 m$

Explanation:

The coefficient of linear expansion of aluminium is

alpha=24*10^-6 (ºC)^-1

Therefore

$\Delta L = \alpha L \Delta T$

$= 24 \cdot {10}^{-} 6 \cdot 1.2 \cdot \left(65 - 15\right)$

$= 1440 \cdot {10}^{-} 6 m$

$= 1.44 \cdot {10}^{-} 3$

The length is

$L + \Delta L = 1.2 + 0.00144 = 1.20144 m$