Question

What is the limit of `1/(lnx)` as x approaches `oo`?

Answer 1

`lim_(x rarr oo) 1/lnx =0`

Explanation:

As `x` increases then `lnx` monotonically increases without bound., so the denominator increases without bound,

Hence, `lim_(x rarr oo) 1/lnx =0`

graph{1/lnx [-3.99, 24.48, -6.45, 7.79]}