# What is the limit of  (2x^2-4x) / (x+1) as x goes to infinity?

Oct 21, 2015

$\infty$

#### Explanation:

${\lim}_{x \to \infty} \frac{2 {x}^{2} - 4 x}{x + 1} = {\lim}_{x \to \infty} \frac{2 x - 4}{1 + \frac{1}{x}} = \infty$

When $x \to \infty$ then $\frac{1}{x} \to 0$.