What is the limit of #(4 x^2 + 4)/(x^2 + 3 x - 2) # as x approaches -2?
1 Answer
Dec 17, 2016
Explanation:
Since the function is neither undefined/indeterminate for x = -2, we can evaluate the limit by substitution.
#rArrlim_(xto-2)(4x^2+4)/(x^2+3x-2)#
#=lim_(xto-2)(16+4)/(4-6-2)=-5#
