What is the limit of #cos(x-9)/sqrt(x-3)# as #x# approaches to 9? Calculus Differentiating Trigonometric Functions Limits Involving Trigonometric Functions 1 Answer kumail Apr 24, 2017 #1/sqrt(6)# Explanation: Since the function is defined at #x = 9#, we can simply evaluate it at #x=9# to obtain the limit, evaluating, we get #cos(0)/sqrt(6) = 1/sqrt(6)# Answer link Related questions How do you find the limit of inverse trig functions? How do you find limits involving trigonometric functions and infinity? What is the limit #lim_(x->0)sin(x)/x#? What is the limit #lim_(x->0)(cos(x)-1)/x#? What is the limit of #sin(2x)/x^2# as x approaches 0? Question #99ee1 What is the derivative of #2^sin(pi*x)#? What is the derivative of #sin^3x#? Question #eefeb Question #af14f See all questions in Limits Involving Trigonometric Functions Impact of this question 2547 views around the world You can reuse this answer Creative Commons License