What is the limit of $\frac{cos (x - 9)}{\sqrt{x - 3}}$ $cos(x-9)/sqrt(x-3)$ as $x$ $x$ approaches to 9?

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What is the limit of $\frac{cos (x - 9)}{\sqrt{x - 3}}$ $cos(x-9)/sqrt(x-3)$ as $x$ $x$ approaches to 9?

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Answer 1 · 2017-04-24T00:06:15

$\frac{1}{\sqrt{6}}$ $1/sqrt(6)$

Explanation:

Since the function is defined at $x = 9$ $x = 9$ , we can simply evaluate it at $x = 9$ $x=9$ to obtain the limit, evaluating, we get $\frac{cos (0)}{\sqrt{6}} = \frac{1}{\sqrt{6}}$ $cos(0)/sqrt(6) = 1/sqrt(6)$

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What is the limit of $\frac{cos (x - 9)}{\sqrt{x - 3}}$ $cos(x-9)/sqrt(x-3)$ as $x$ $x$ approaches to 9?

1 Answer

Explanation:

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What is the limit of cos(x-9)/sqrt(x-3)cos(x−9)√x−3cos(x-9)/sqrt(x-3) as xxx approaches to 9?

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What is the limit of $\frac{cos (x - 9)}{\sqrt{x - 3}}$ $cos(x-9)/sqrt(x-3)$ as $x$ $x$ approaches to 9?