Question

What is the limit of `f(x)=x/(e^(x^2)))` as x approaches infinity? 

Answer 1

I think it should be zero;
If you do the limit directly you should get`oo/oo`;
If you apply the de l'Hospital Rule (derive numerator and denominator and then do the limit);
`lim_(x->oo)(1/(2xe^(x^2)))=0`