What is the limit of sqrt(x+4)/(x+4) as x goes to infinity?

$0$
$\frac{\sqrt{x + 4}}{x + 4} = \frac{1}{\sqrt{x + 4}}$ so
${\lim}_{x \to \infty} \frac{\sqrt{x + 4}}{x + 4} = {\lim}_{x \to \infty} \frac{1}{\sqrt{x + 4}} = 0$