What is the limit of #(x^2 - 7x)/(x+1)# as x goes to infinity? Calculus Limits Limits at Infinity and Horizontal Asymptotes 1 Answer GiĆ³ Oct 17, 2015 I would say #oo#: Explanation: Consider: #lim_(x->oo)((x^2-7x)/(x+1))=# collecting #x^2# and #x#: #lim_(x->oo)((x^cancel(2)(1-7/x))/(cancel(x)(1+1/x)))=# as #x->oo# then #1/x^n->0# so: #(oo(1-0))/(1+0)=oo# Answer link Related questions What kind of functions have horizontal asymptotes? How do you find horizontal asymptotes for #f(x) = arctan(x)# ? How do you find the horizontal asymptote of a curve? How do you find the horizontal asymptote of the graph of #y=(-2x^6+5x+8)/(8x^6+6x+5)# ? How do you find the horizontal asymptote of the graph of #y=(-4x^6+6x+3)/(8x^6+9x+3)# ? How do you find the horizontal asymptote of the graph of y=3x^6-7x+10/8x^5+9x+10? How do you find the horizontal asymptote of the graph of #y=6x^2# ? How can i find horizontal asymptote? How do you find horizontal asymptotes using limits? What are all horizontal asymptotes of the graph #y=(5+2^x)/(1-2^x)# ? See all questions in Limits at Infinity and Horizontal Asymptotes Impact of this question 2816 views around the world You can reuse this answer Creative Commons License