What is the limits of : #LIM_(x->0) (e^(2x)-1)^(x^2)# ?
1 Answer
May 9, 2018
Explanation:
#(e^(2x)-1)^(x^2)=e^(ln(e^(2x)-1)^(x^2))=e^(x^2ln(e^(2x)-1)#
Using L'Hospital Rules we get:
As a result,
Set