What is the line of symmetry for the parabola whose equation is #y=x^2-12x+7#?

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Answer 1 · 2018-04-05T06:04:40

#x = 6#

Here's how I did it:

To find the line of symmetry for a parabola, we use the formula #x = -b/(2a)#

Your equation #y = x^2 - 12x + 7# is in standard form, or #y = ax^2 + bx + c#. This means that:
#a = 1#

#b = -12#

#c = 7#

Now we can plug in these values into the equation:
#x = (-(-12))/(2(1))#

And now we simplify:
#x = 12/2#

Finally,
#x = 6#