Question

What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge?

Answer 1

`5.6xx10^(11)"N/C"`

Explanation:

The electric field strength is the force per unit charge.

It is given by:

`F=(1)/(4piepsilon_0).Q/r^2`

`1/(4piepsilon_0)` is a constant and has the value `9xx10^9"m/F"`

`:.F=9xx10^9xx(0.0035)/(0.0075^2)`

`:.F=5.6xx10^(11)"N/C"`