Question

What is the magnitude of the electrostatic force of a 1.5 x 10–3 c charge located 1.5 m away?

Answer 1

For a electrostatic force to act you need a minimum of two charges.
So , i consider the other charge to be very negligible.

Explanation:

electrostatic force `F = (k * q1 * q2)/r^2` , where k = `9 * 10^9(approx)` , q1 and q2 are the charges and r is the distance between them(in m) .

`F = (9 * 10^9 * 1.5 * 10^-3 )/(1.5)^2` = `6 * 10^6 N`

Actually , since one of the charges is very very small , we say that Force is actually the value of electric field intensity at that point due to the bigger charge.