# What is the mass of 0.015 moles of Ca(OH)_2?

Calcium hydroxide has a formula mass of $74.09$ $g \cdot m o {l}^{-} 1$.
To find the mass of $0.015$ moles of this stuff simply multiply this by the molar mass:
$74.09$ $g \cdot \cancel{m o {l}^{-} 1}$ $\times$ $0.015$ $\cancel{m o l}$ $=$ ??g