# What is the mass of 1.7 times 10^23 atoms of zinc?

##### 1 Answer
Jul 30, 2017

Approx. $20 \cdot g$........

#### Explanation:

$6.022 \times {10}^{23}$ individual zinc atoms have a mass of $65.39 \cdot g$, and thus to get the mass of $1.7 \times {10}^{23} \cdot \text{zinc atoms}$ have a mass of......

(1.7xx10^23*"zinc atoms")/(6.022xx10^23*"zinc atoms"*mol^-1)xx65.39*g*mol^-1=?*g

From where did I get the number $6.022 \times {10}^{23}$? Is this in any way special?