# What is the mass of 1.87 moles of barium chloride?

$1$ $m o l$ of $B a C {l}_{2}$ has a mass of $208.23$ $g$.
So, $1.87$ $\cancel{m o l}$ $\times$ $208.23$ $g \cdot \cancel{m o {l}^{-} 1}$ $=$ ?? $g$