# What is the mass of 2.6 mol of lithium bromide?

$1$ mol of lithium bromide has a mass of $86.85$ $g \cdot m o {l}^{-} 1$. You have $2.6$ moles of the stuff.
So mass $=$ $86.85$ $g \cdot \cancel{m o {l}^{-} 1}$$\times$ $2.6$ $\cancel{m o l}$ $=$ ?? $g$.