# What is the mass of 2.75 mol of sodium hydrogen carbonate, NaHCO_3?

$N a H C {O}_{3}$ has a formula mass of $84.01 \cdot g \cdot m o {l}^{-} 1$.
So if there are $2.75 \cdot m o l$, this has a mass of $2.75 \cdot m o l \times 84.01 \cdot g \cdot m o {l}^{-} 1$ $=$ ??*g.