# What is the mass of 20.0 mL of nitrogen gas?

Apr 11, 2018

#### Answer:

Well we must specify a pressure of $1 \cdot a t m$ and a temperature of $298 \cdot K$...

#### Explanation:

And we solve for $n$ in the old Ideal Gas equation....

$n = \frac{P V}{R T} = \frac{1 \cdot a t m \times 20.0 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1}{0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \cdot 298 \cdot K}$

And I make this about $8 \times {10}^{-} 4 \cdot m o l$ with respect to dinitrogen...