Question

What is the mass of 20.0 mL of nitrogen gas?

Answer 1

Well we must specify a pressure of `1*atm` and a temperature of `298*K`...

Explanation:

And we solve for `n` in the old Ideal Gas equation....

`n=(PV)/(RT)=(1*atmxx20.0*mLxx10^-3*L*mL^-1)/(0.0821*(L*atm)/(K*mol)*298*K)`

And I make this about `8xx10^-4*mol` with respect to dinitrogen...