What is the mass of 3.8*10^24 atoms of argon?

1 Answer
anor277
Oct 17, 2016

3.8xx10^24 argon atoms have a mass of approx. 250*g.

Explanation:

6.022xx10^23 argon atoms have a mass of 39.95*g. How do I know this? Well, 6.022xx10^23 is "Avogadro's number", and the Periodic Table lists the mass of "Avogadro's number of each atom".

And thus we calculate the product:

(3.8xx10^24" argon atoms")/(6.022xx10^23" argon atoms mol"^-1)xx39.95*g*mol^-1 = ??g

Argon is often used in the laboratory to provide a protective blanket of inert gas for reactions with air and water sensitive reagents. Why should argon be unreactive towards the reagents?

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