What is the mass of #3.8*10^24# atoms of argon?

1 Answer
anor277
Oct 17, 2016

#3.8xx10^24# argon atoms have a mass of approx. #250*g#.

Explanation:

#6.022xx10^23# argon atoms have a mass of #39.95*g#. How do I know this? Well, #6.022xx10^23# is #"Avogadro's number"#, and the Periodic Table lists the mass of #"Avogadro's number of each atom"#.

And thus we calculate the product:

#(3.8xx10^24" argon atoms")/(6.022xx10^23" argon atoms mol"^-1)xx39.95*g*mol^-1# #=# #??g#

Argon is often used in the laboratory to provide a protective blanket of inert gas for reactions with air and water sensitive reagents. Why should argon be unreactive towards the reagents?

Related questions
See all questions in The Mole
Impact of this question
17200 views around the world
You can reuse this answer
Creative Commons License