What is the mass of 4.18 equiv Mg(OH)2 in a complete neutralization reaction?

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Answer 1 · 2018-04-14T10:08:41

#"8.36 g"#

#"Equivalent mass" = "Mass"/"n - factor"#

In neutralisation reaction of #"Mg(OH)"_2# n-factor is #2#, because it gives #"2 OH"^-# ions.

#"Mass = Equivalent mass × 2 = 4.18 g × 2 = 8.36 g"#