# What is the mass of 4.22 x10^23 atoms of lead (Pb)?

Apr 9, 2017

$\frac{4.22 x {10}^{23}}{6.022 x {10}^{23}} = .7008 m o l P b$
$.7008 m o l P b \left(207.2 \frac{g}{m o l}\right)$=145.198
We divide by Avogadro's number in the first step since per mole there are $6.022 x {10}^{23}$ atoms then from mols use the molar mass of lead to find how many grams of lead