What is the mass of #4.22 x10^23# atoms of lead (Pb)?

1 Answer
Apr 9, 2017


145 g of Pb


#(4.22 x 10^23)/ (6.022 x10^23)= .7008 mol Pb#
#.7008mol Pb (207.2 g/(mol))#=145.198
The answer is significant to three digits so rounded this would be 145 g Pb

We divide by Avogadro's number in the first step since per mole there are #6.022x10^23# atoms then from mols use the molar mass of lead to find how many grams of lead