What is the mass of #4.49*10^25# particles of #HCl#?

1 Answer
Mar 8, 2016

Answer:

#"Number of HCl particles"/"Number of HCl particles per mol"# #xx36.5*g*mol^-1# #=# #??#

Explanation:

It is a fact that #6.022xx10^23# individual #HCl# particles have a mass of #36.5# #g#. This is simply another way of saying that the molar mass of #HCl#, the mass of #"Avogadro's Number"# of #HCl# particles, is #36.5*g*mol^-1#.

So, all we have to do is divide the given number by Avogadro's number to get the number of moles, and then multiply this number by the molar mass:

#"Number of HCl particles"/"Number of HCl particles per mol"# #xx36.5*g*mol^-1# #=# #(4.49xx10^25)/(6.022xx10^23)# #xx# #36.5*g# #=# #??# #g#