# What is the mass of 4.50 moles of silver sulfate?

Mar 14, 2017

The mass of $\text{4.50}$ moles of silver sulfate is $1.40 \times {10}^{3} \text{g}$.

#### Explanation:

Molar mass is the mass of one mole of a substance. One mole of silver sulfate $\left(\text{Ag"_2"SO"_4}\right)$ is $\text{311.792 g/mol}$.
https://www.ncbi.nlm.nih.gov/pccompound/?term=silver+sulfate

Multiply the given moles by the molar mass.

4.50 color(red)cancel(color(black)("mol Ag"_2"SO"_4))xx(311.792"g Ag"_2"SO"_4)/(color(red)(cancel(color(black)("mol Ag"_2"SO"_4))))="1400 g Ag"_2"SO"_4=1.40xx10^3"g" (rounded to three significant figures)